2.x^2+1=51

Solution for 2.x^2+1=51 equation:

2.x^2+1=51

We move all terms to the left:

2.x^2+1-(51)=0

We add all the numbers together, and all the variables

2.x^2-50=0

a = 2.; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·2.·(-50)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*2.}=\frac{-20}{4}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*2.}=\frac{20}{4}
=5
$